The lower right cell shows a house edge of 10.65%. I do not know what is the most common win, but the following return table shows the odds for a win of 150 to 1. That’s how it is for every bet on a double-zero. The 2 house profit divided by the 38 risk, multiplied by 100 yields a 5.26 percent house edge. Since your risk was 38, that gives the house a 2 profit. Again that leaves you with 36 at the end of the sequence. There is also a version of 2G'$ for triple-zero roulette. A triple zero roulette table layout at the New York New York casino in Las Vegas. Divide that by the one-unit original bet and you have a house edge of 5.33% by parlaying, relative to the initial bet. If the player parlays, his expected loss between the two bets is the sum of 1/37 = 0.0270 units from the first bet and an average of (1/37)*36*(1/37) = 0.0263 from the possible second bet for a total of 0.0533 units. The answer has to do with the way the house edge is defined. The astute reader may wonder why the player should accept a win of 1,300, at a house edge of 4.97%, rather than parlay, when the house edge in single-zero roulette is 2.70%. While this opens for additional betting options, it also lowers the RTP of the.
Thus, I would do that rather than accept a win of 1,275 or less. The roulette wheel in American roulette has one additional slot, a double-zero. By parlaying a first win on zero himself, the player can achieve a win for two consecutive zeros of 1,296 to 1.
